Printing Patterns Using Asterisks in c++

It is a very common question for both C and C++ programmers that printing a diamond shape using asterisks (*) and this question is going to be ask in almost every freaking semester .There are a lot of different ways to do that. But among them I found this one easier. Those who likes to use C code for printing diamond just change the header #include<iostream> to #include<stdio.h>, cout to printf and cin to scanf.Lets start the fun –

#include<iostream>

#include<cstdlib>

using namespace std;

int main()

{

int i=0, j=0, NUM=3;

for(i=-NUM; i<=NUM; i++)

{

for(j=-NUM; j<=NUM; j++)

{

if( abs(i)+abs(j)<=NUM) // Change this condition

 { cout<<"*"; }

else { cout<<" ";}

}

cout<<endl;

}
return 0;
}

The above code will prints-

 *

***

*****

*******

*****

***

*

 Wait I haven’t done yet. You can have fun with it. Just change the ‘ if ‘ condition. You will get new design . Wanna see???. Lets take a look-

if( abs(i)*abs(j)<= NUM)

prints-

***
***
*******
*******
*******
***
***

if( abs(i)*abs(j)<= NUM)

prints-

*
*  *
*      *
*          *
*      *
*  *
*

if(abs(i)==abs(j)

prints-

*          *
*      *
*  *
*
*  *
*      *
*          *

if( abs(i)==0||abs(j)==0)

prints-

*
*
*
*******
*
*
*

if(abs(i)>=abs(j))

prints-

*******
*****
***
*
***
*****
*******

if(abs(i)<=abs(j))

prints-

*          *
**      **
***  ***
*******
***  ***
**      **
*          *

That’s it. Just change the condition and have fun with it. ENJOY !